Question

hello there can you please help me posted picture of question

Answer 1

5x^2+2x-3=0
We can use the quadratic formula:
ax^2+bx+c=0; a=5, b=2, c=-3
x=[-b+-sqrt(b^2-4ac)]/(2a)
x=[-(2)+-sqrt((2)^2-4(5)(-3))]/[2(5)]
x=[-2+-sqrt(4+60)]/10
x=[-2+-sqrt(64)]/10
x=(-2+-8)/10
Two solutions:
x1=(-2-8)/10→x1=(-10)/10→x1=-1
x2=(-2+8)/10→x2=6/10→x2=3/5

Answer: x=-1 and x=3/5

Answer: Options D. x=-1 and F. x=3/5

Answer 2

using quadratic formula;
LET:
a=5, b=2, c=-3

x=[-b+-sqrt(b^2-4ac)]/(2a)x=[-(2)+-sqrt((2)^2-4(5)(-3))]/[2(5)]x=[-2+-sqrt(64)]/10x=(-2+-8)/10
x1=-1x2=3/5