Respuesta :

[tex](5x - 2)^2 = 15[/tex]

Square root both sides:
[tex]5x - 2 = \pm\sqrt{15} [/tex]

Add 2 to both sides:
[tex]5x = pm\sqrt{15} + 2[/tex]

Divide both sides by 5:
[tex]x = \dfrac{ \pm\sqrt{15} + 2}{5} [/tex]

Answers:
[tex]x = \dfrac{ \sqrt{15} + 2}{5} \ or \ \dfrac{ - \sqrt{15} + 2}{5} [/tex]

Answer: (B) and (E)

Ans: Option (B) and Option (E)

Explanation:

Given equation:
(5x-2)^2 = 15

Take square-root on both sides:
[tex] \sqrt{(5x-2)^2} = \sqrt{15} \\ 5x - 2 = \pm \sqrt{15} \\ x = \frac{ \pm \sqrt{15} + 2}{5} [/tex]

Also plus-minus are involved, hence Options (B) and (E) are both correct.
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