Ans: Option (B) and Option (E)
Explanation:
Given equation:
(5x-2)^2 = 15
Take square-root on both sides:
[tex] \sqrt{(5x-2)^2} = \sqrt{15} \\ 5x - 2 = \pm \sqrt{15} \\ x = \frac{ \pm \sqrt{15} + 2}{5} [/tex]
Also plus-minus are involved, hence Options (B) and (E) are both correct.