Answer:
The roots are: [tex] \frac{ \sqrt{3} + 3 }{2} [/tex] and [tex] \frac{- \sqrt{3} + 3 }{2} [/tex]
Explanation:
First, we would need to put the equation is standard form which is as follows:
ax² + bx + c = 0
This can be done as follows:
4x² - 12x + 9 - 3 = 0
4x² - 12x + 6 = 0
By comparison, we would find that:
a = 4
b = -12
c = 6
To get the roots, we would substitute in the quadratic formula shown in the attached image.
Doing this, we would find that:
either x = [tex] \frac{ \sqrt{3} + 3 }{2} [/tex]
or x = [tex] \frac{- \sqrt{3} + 3 }{2} [/tex]
Hope this helps :)
