Answer:
The solutions are: 5 and 7
Explanation:
First we would need to put the equation in the standard form which is:
ax² + bx + c = 0
This can be done as follows:
x² - 7x + 38 = 5x + 3
x² - 7x + 38 - 5x - 3 = 0
x² - 12x + 35 = 0
By comparison:
a = 1
b = -12
c = 35
Now, to get the roots, we would need to use the quadratic formula attached in the images.
By substitution, we would find that:\
either x = [tex] \frac{12+ \sqrt{(-12)^2-4(1)(35)} }{2(1)} = 7[/tex]
or x = [tex] \frac{12- \sqrt{(-12)^2-4(1)(35)} }{2(1)} = 5[/tex]
Hope this helps :)
