Question

A community park is shaped like a trapezoid with a height of 30 yd, a top base of 25 yd, and a bottom base of 33 yd. The park has a circular fountain whose radius is 4 yd.

What is the area of the park without the fountain? do not round

Use 3.14 for pi.

All points possible and to the first one who answers the question right gets brainliest.

Answer 1

The area (A) will be area of trapezoid (At) - area of circular fountain (Ac)
At = 1/2 (b1+b2) × h = 1/2 (25+33)×30
= 29×30 = 870 sq.yds.
Ac = pi×r^2 = (3.14)(4)^2 = 3.14×16
= 50.24 sq.yds
At - Ac = (b × h) - (pi×r^2) = 870- 50.24
= 819.76 sq.yds

Answer 2

Area of trapezoid: 1/2h(b₁ + b₂)
Words: 1/2(height)(sum of bases)

Plug the numbers in to the formula.

1/2(30)(25 + 33) = 870 yd²

Now find the area of the fountain.
Use $\pi r^2$.

$\pi 4^2$ = 50.24 yd²

Subtract 50.24 from 870.
870 - 50.24 = 819.76 

The area of the park without the fountain is 819.76 yd².