Answer:
The roots of the equation are -4 and -5
Explanation:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
3x² + 27x + 60 = 0
By comparison, we could find that:
a = 3
b = 27
c = 60
Now, to get the roots we would use the quadratic formula shown in the attached image.
By substituting, we would find that:
either x = [tex] \frac{-27+ \sqrt{(27)^2-4(3)(60)} }{2(3)} = -4[/tex]
or x = [tex] \frac{-27- \sqrt{(27)^2-4(3)(60)} }{2(3)} = -5[/tex]
This means that the roots of the equation are -4 and -5
Hope this helps :)
