Question

for problems 6-7, find the surface area of the regular rpyramids shown to the nearest whole number.

6.
72ft
128ft
56ft
22ft

7.
1300m2
390m
650m2
628m2

Answer 1

6. Base = 4*4 = 16
1 side = 1/2 x 4 x 7 = 14
14 x 4 sides = 56

total: 56 + 16 = 72 ft^2

7. 
base = 1/2 x perimeter x apathem
base = 1/2*(6*10) * 5sqrt3
base = 259.81 round to 260

1 side = 1/2 x 10 x 13 = 65
6 sides = 65 *6 = 390

total = 390 + 260 = 650 m^2

Answer 2

6. Base = $4 \times 4 = 16$

1 side = $\dfrac{1}{2} \times 4 \times 7 = 14$

$14 \times 4 = 56$

Total area
$= 56 + 16 \\ = 72 {ft}^{2}$

7.
$\dfrac{1}{2} \times (6 \times 10) \times 5 \sqrt{3} = 259.81$

$\dfrac{1}{2} \times 10 \times 13 = 65$

$65 \times 6 = 390$

Total area =
$390 + 260 = 650 {m}^{2}$


Hope this helps. - M