Respuesta :

s1m1
Third option from the. Top to the bottom

Answer:

[tex]\frac{3a^2b^{11}}{2}[/tex]

Step-by-step explanation:

[tex]\frac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}[/tex]

To simplify the given expression we use exponential property

[tex]\frac{-18}{-12} =\frac{3}{2}[/tex]

[tex]\frac{x^m}{x^n} =x^{m-n}[/tex]

[tex]\frac{a^{-2}}{a^{-4}} =a^{-2+4}=a^2[/tex]

[tex]\frac{b^{5}}{b^{-6}} =b^{5+6}=b^{11}[/tex]

We substitute the simplified terms

[tex]\frac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}[/tex]

[tex]\frac{3a^2b^{11}}{2}[/tex]

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