A - juice is not sugar free
B - juice is not grape juice
[tex] |\Omega|=27\\
|A|=13\\
|A\cap B|=3\\\\
P(A)=\dfrac{13}{27}\\
P(A\cap B)=\dfrac{3}{27}=\dfrac{1}{9}\\\\
P(B|A)=\dfrac{\dfrac{1}{9}}{\dfrac{13}{27}}=\dfrac{1}{9}\cdot\dfrac{27}{13}=\dfrac{3}{13}[/tex]
So, it's D, assuming "3 13" meant [tex]\dfrac{3}{13}[/tex]