Respuesta :
3 - 3√3a
= -----------------
4√8a
3 - 3√3a
= -----------------
8√2a
(3 - 3√3a) √2a
= ----------------------
8 √2a √2a
3√2a - 3a√6
= ----------------------
16a
3(√2a - a√6)
= ----------------------
16a
hope it helps
= -----------------
4√8a
3 - 3√3a
= -----------------
8√2a
(3 - 3√3a) √2a
= ----------------------
8 √2a √2a
3√2a - 3a√6
= ----------------------
16a
3(√2a - a√6)
= ----------------------
16a
hope it helps
So, to simplify, find what can be changed and what can't.
You can get rid of a, because whether they are both inside or out of a square root function (can't be mixed), they can be gotten rid of.
So, you will end up with [tex] \frac{3-3 \sqrt{3} }{4 \sqrt{8} } [/tex].
But, that's not the simplest form.
The square root on the bottom still can be simplified.
So, find a factor in 8 that can have a perfect square. 2,4
2,2,2
Since 4 is a perfect squared (you find a pair of multiples when factored again), the simple version is 2[tex] \sqrt{2} [/tex], but you have to multiply the number on the outside by the number already there.
4×2=8
So, your simplest equation would be [tex] \frac{3-3 \sqrt{3} }{8 \sqrt{2} } [/tex].
You can get rid of a, because whether they are both inside or out of a square root function (can't be mixed), they can be gotten rid of.
So, you will end up with [tex] \frac{3-3 \sqrt{3} }{4 \sqrt{8} } [/tex].
But, that's not the simplest form.
The square root on the bottom still can be simplified.
So, find a factor in 8 that can have a perfect square. 2,4
2,2,2
Since 4 is a perfect squared (you find a pair of multiples when factored again), the simple version is 2[tex] \sqrt{2} [/tex], but you have to multiply the number on the outside by the number already there.
4×2=8
So, your simplest equation would be [tex] \frac{3-3 \sqrt{3} }{8 \sqrt{2} } [/tex].