Answer:
[tex]3 \sqrt{2} x^2 y^{3/2} [/tex]
This can be rewritten as:
[tex]3x^2 \sqrt{2y^3} [/tex]
Explanation:
Before we begin, remember the following:
√ab = √a * √b
√xᵃ = x^(a/2)
Now, for the given, we have:
[tex] \sqrt{18x^4y^3} [/tex]
18 can be rewritten as 9 * 2
Therefore, the given expression would now become:
[tex] \sqrt{9*2x^4y^3} [/tex]
Distributing the root as mentioned in the above rules, we would get:
[tex] \sqrt{9} * \sqrt{2} * \sqrt{x^4} * \sqrt{y^3}
[/tex]
We know that:
[tex] \sqrt{9} = 3[/tex] (we would disregard the negative value of the root)
[tex] \sqrt{x^4} = x^{4/2} = x^2[/tex]
[tex] \sqrt{y^3} = y^{3/2} [/tex]
Substitute with the above in the expression, we would get the final answer:
[tex]3 \sqrt{2} x^2 y^{3/2} [/tex]
This can be rewritten as:
[tex]3x^2 \sqrt{2y^3} [/tex]
Hope this helps :)