Respuesta :

√18x^4y^3
= 3x^2y√(2y)

hope it helps
Louli
Answer:
[tex]3 \sqrt{2} x^2 y^{3/2} [/tex]
This can be rewritten as:
[tex]3x^2 \sqrt{2y^3} [/tex]

Explanation:
Before we begin, remember the following:
√ab = √a * √b
√xᵃ = x^(a/2)

Now, for the given, we have:
[tex] \sqrt{18x^4y^3} [/tex]

18 can be rewritten as 9 * 2
Therefore, the given expression would now become:
[tex] \sqrt{9*2x^4y^3} [/tex]

Distributing the root as mentioned in the above rules, we would get:
[tex] \sqrt{9} * \sqrt{2} * \sqrt{x^4} * \sqrt{y^3} [/tex]

We know that:
[tex] \sqrt{9} = 3[/tex] (we would disregard the negative value of the root)
[tex] \sqrt{x^4} = x^{4/2} = x^2[/tex]
[tex] \sqrt{y^3} = y^{3/2} [/tex]

Substitute with the above in the expression, we would get the final answer:
[tex]3 \sqrt{2} x^2 y^{3/2} [/tex]
This can be rewritten as:
[tex]3x^2 \sqrt{2y^3} [/tex]

Hope this helps :)
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