Identify the balanced single displacement reaction.
CuCl2 + Fe ⟶ 2Cu + FeCI2
PbCl4 + 2Ca(OH)2 ⟶ 2CaCl2 + Pb(OH)4
CuCl2 + Fe ⟶ Cu + FeCI2
PbCl4 + 2Ca(OH)2 ⟶ 2CaCl2 + 4Pb(OH)

Respuesta :

CuCl2 + Fe ⟶ Cu + FeCI2

Answer: [tex]CuCl_2+Fe\rightarrow Cu +FeCI_2[/tex]

Explanation:

This is a single replacement reaction in which iron replaces copper from its salt solution. As iron is more reactive than copper , it easily loses electrons to convert to [tex]Fe^{2+}[/tex] in [tex]FeCl_2[/tex] and [tex]Cu^{2+}[/tex] in [tex]CuCl_2[/tex] accepts electrons to form [tex]Cu[/tex].

The equation is also balanced as equal number of atoms of each element are present on reactant and product side.

1. [tex]CuCl_2+Fe\rightarrow 2Cu +FeCI_2[/tex]: The equation is not balanced.

2. [tex]PbCl_4+2Ca(OH)_2\rightarrow 2CaCl_2+Pb(OH)_4[/tex]: This is a double displacement reaction and is balanced.

4.  [tex]PbCl_4+2Ca(OH)_2\rightarrow 2CaCl_2+4Pb(OH)_4[/tex]: This is a double displacement reaction and is not balanced.

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