Question

Construct a parallelogram ABCD such that AB=9 Cm, BC=6cm and ABC=115 degress.

(1) measure and write down the length of the diagonal BD

(2) construct the perpendicular bisector of AB such that it cuts CD. Measure and write down the length of AT, Such that T is the point where the perpendicular bisector of AB cuts CD

Answer 1

1.BD=AC
AC^2=(9^2)+(6^2)-2(9)(6)COS115
AC^2=117-108COS115
AC=√71.358
AC=8.447//

Answer 2

Answer:

1.BD=AC

AC^2=(9^2)+(6^2)-2(9)(6)COS115

AC^2=117-108COS115

AC=√71.358

AC=8.447//1.BD=AC

AC^2=(9^2)+(6^2)-2(9)(6)COS115

AC^2=117-108COS115

AC=√71.358

AC=8.447//

Step-by-step explanation: