Question

A bag contains 5 blue marbles and 8 orange marbles. Polly draws a marble from the bag and keeps the marble. Perry then draws a marble from the bag. What is the probability that both Polly and Perry draw an blue marble from the bag?



5/39

39/5

9/25

1

Answer 1

did u ever figure out the question? 

Answer 2

There are a total of 13 marbles in the bag. (5 blue marbles and 8 orange marbles)

We know that Polly draws first. She draws the marble from the bag and keeps the marble. Now, let "A" be the event that Polly draws a blue marble from the bag. Then the probability of the event A occurring will be given by:

$P(A)=\frac{5}{13}$

Now, given that Polly has already drawn a blue marble from the bag we know that the total number of marbles in the bag will now get reduced by 1 and thus will become 12. Likewise, the total number of blue marbles will become 4.

Let "B" be the event that Perry draws a blue marble from the bag. The probability of the event B occurring is:

$P(B)=\frac{4}{12}=\frac{1}{3}$

Thus, the the probability that both Polly and Perry draw an blue marble from the bag will be given by:

P(A and B)=$P(A)\times P(B)=\frac{5}{13}\times \frac{1}{3} =\frac{5}{39}$

Out of the given options, the first option in the correct one. The answer is $\frac{5}{39}$.