Question

Enter the y coordinate of the solution to this system of equations -2x+3y=-6. 5x-6y=15

Answer 1

did u want elimination method? if so I got (3,0)

Answer 2

The equations given to us are:

$-2x+3y=-6$.........(Equation 1)

and $5x-6y=15$...(Equation 2)

Let us now isolate x in (Equation 1) by 3y from both sides and dividing by -2. We will get:

$x=\frac{6+3y}{2}$......(Equation 3)

Likewise, in order to isolate x in (Equation 2), we will have to add 6y to both sides and divide by 5. We will get:

$x=\frac{15+6y}{5}$.....(Equation 4)

Equating the right sides of both the equations 3 and 4 we get:

$\frac{6+3y}{2}=\frac{15+6y}{5}$

Cross-multiplication will give us:

$30+15y=30+12y$

Cancelling 30 from both sides will give us:

$15y=12y$

Subtracting 12y from both sides we get:

$15y-12y=3y=0$

Thus, $y=0$

This is the required y coordinate of the solution to this system of equations.

Thus, y=0 is the answer.