These 2 figures A and B have the ratio k=3/5
Si SA is the lenght of a side, so SA of figure B is 30:3/5=30x5/3=50
Si SA is area , so SA of figure B is 30:k^2= 30:9/25= 30x25/9= 250/3
About the problem 3, we have the formula
V= 1/3[tex] \pi [/tex](r^2+ R^2+rR)h=
V= 1/3[tex] \pi (2^2+5^2+2x5)15=[/tex]
V=195[tex] \pi [/tex]
