Question

A 7.100 L sample of gas is cooled from 73.0 °C to a temperature at which its volume is 5.700 L. What is this new temperature? Assume no change in pressure of the gas.

Answer 1

The  mew  temperature  of  a  sample of   gas  is  calculated  using Charles  law  formula

that  is  v1/T1  = V2/T2
V1=  7.100 L
T1=73 + 273 = 346 K
V2 = 5.700 L
T2=?

by  making the  T2  the   subject  of the  formula
T2 =V2T1/V1

T2= 5.700 x  346/7.100 =277.8 K