Respuesta :
Answer: Option C. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.
First equation of system A multiplied by -3:
(-3)(x+6y=5)
(-3)(x)+(-3)(6)=(-3)(5)
-3x-18=-15
Sum of the second equation of system A and the first equation multiplied by -3:
(-3x-18)+(3x-7y)=(-15)+(-35)
-3x-18+3x-7y=-15-35
-25y=-50
System B
x+6y=5
-25y=-50
First equation of system A multiplied by -3:
(-3)(x+6y=5)
(-3)(x)+(-3)(6)=(-3)(5)
-3x-18=-15
Sum of the second equation of system A and the first equation multiplied by -3:
(-3x-18)+(3x-7y)=(-15)+(-35)
-3x-18+3x-7y=-15-35
-25y=-50
System B
x+6y=5
-25y=-50
Answer:
C. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.
Step-by-step explanation:
System A
x + 6y = 5
3x - 7y = -35
Solution: (-7, 2)
System B
x + 6y = 5
-25y = -50
First equation is same in both system A and B
To get system B, the second equation in system A was replaced by sum of that equation and first equation multiplied by -3
x + 6y = 5 (Multiply by -3)
-3x -18y =-15
now do the sum of 3x - 7y = -35 and -3x -18y =-15
3x - 7y = -35
-3x -18y =-15
-----------------------
-25 y = -50
The solution to system B will be the same as the solution to system A.