Respuesta :

[tex]\boxed { \boxed { a_n = a_1 + d(n - 1)}}[/tex]

[tex]\text{Given } a_1 = -2 , d = 3, [/tex]

[tex]a_n = - 2 + 3(n - 1)[/tex]

[tex]a_n = - 2 + 3n - 3[/tex]

[tex]a_n = 3n - 5[/tex]

[tex]\boxed{\boxed {\text {Answer : }a_n = 3n - 5 }}[/tex]

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