E/Nucleon = mc^2
Where
m= number of protons*mass of a proton+Number of neutrons*mass of a neutron
For 48Ti, Protons = 22, Neutrons = 26. Protons and Neutrons weigh almost equal at 1.673*10^-27 kg
While 1 amu = 1.661*10^-27 kg
Therefore,
m= {(22+26)*1.673*10^-27}-{47.9359*1.661*10^-27} = 6.8247*10^-28 kg
c= speed of light = 3*10^8 m/s
Then,
Binding energy per nucleon = {6.8247*10^-28*(3*10^8)^2}/48 = 1.28*10^-12 J
