If an object is shot with an initial velocity of 160 ft/sec, what is the smallest initial angle will you need to obtain a horizontal distance of 500 feet? (Round to the nearest hundredth of a radian.) Please show work
To solve the question we shall use the formula for the range given by: Horizontal range, R=[v²sin 2θ]/g plugging in our values we get: 500=[160²×sin 2θ]/10 5000=160²×sin 2θ 0.1953=sin 2θ thus: arcsin 0.1953=2θ 11.263=2θ hence: θ=5.6315°~5.63
