Question

A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?

Answer 1

Hello!

To solve this problem we're going to use the Charles' Law. This Law describes the relationship between Volume and Temperature in an ideal gas. Applying this law we have the following equation:

$\frac{V1}{T1} = \frac{V2}{T2} \\ \\ T2= \frac{V2*T1}{V1}= \frac{235 mL * 105 ^{\circ}C }{455 mL}=54,23 ^{\circ}C$

So, the final temperature is 54,23 °C

Have a nice day!

Answer 2

Answer : The final temperature of gas will be, $73.4^oC$

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

or,

$\frac{V_1}{V_2}=\frac{T_1}{T_2}$

where,

$V_1$ = initial volume of gas = 445 ml

$V_2$ = final volume of gas = 235 ml

$T_1$ = initial temperature of gas = $105^oC=273+105=378K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

$\frac{445ml}{235ml}=\frac{378K}{T_2}$

$T_2=199.6K=73.4^oC$

conversion  used : $K=273+^oC$

Therefore, the final temperature of gas will be, $73.4^oC$