Water flows from the bottom of a storage tank at a rate of r(t) = 200 − 4t liters per minute, where 0 ≤ t ≤ 50. find the amount of water that flows from the tank during the first 35 minutes.

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Answer:

The amount of water that flows from the tank during the first 35 minutes is 4550 liters.

Step-by-step explanation:

We know that the rate is given by [tex]r(t)=200-4t[/tex] and the problem asks for the net change (the amount of water) for the first 35 minutes.

We can use the Net change theorem:

The integral of a rate of change is the net change:

[tex]\int\limits^b_a {F'(x)} \, dx =F(b)-F(a)[/tex]

Applying the above theorem we get

[tex]\int\limits^{35}_0 {200-4t} \, dt[/tex]

[tex]\int _0^{35}200dt-\int _0^{35}4tdt\\\\\left[200t\right]^{35}_0-\left[\frac{t^2}{2}\right]^{35}_0\\\\7000-2450\\\\4550[/tex]

The amount of water that flows from the tank during the first 35 minutes is 4550 liters.

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