Question

The frequency of a photon that has an energy of 3.7 × 10-18 j is ________ s-1.

Answer 1

Answer: The frequency of the photon is $5.58\times 10^{15}s^{-1}$

Explanation:

The relationship between energy and frequency is given by Planck's equation, which is:

$E=h\nu$

where,

h = Planck's constant = $6.626\times 10^{-32}Js$

E = energy of the photon = $3.7\times 10^{-18}J$

$\nu$ = frequency of photon = ?

Putting values in above equation, we get:

$3.7\times 10^{-18}J=6.626\times 10^{-34}Js\times \nu\\\\\nu=\frac{3.7\times 10^{-18}J}{6.626\times 10^{-34}Js}=5.58\times 10^{15}s^{-1}$

Hence, the frequency of the photon is $5.58\times 10^{15}s^{-1}$

Answer 2

We have that for the Question it can be said that The frequency of a photon that has an energy of 3.7 × 10-18 j is

$f-=5.58*10^{51}Hz$

From the question we are told

he frequency of a photon that has an energy of 3.7 × 10-18 j is

Generally the equation for the Frequency  is mathematically given as

$f=\frac{V}{lambda}$

and

$E=hf$

Therefore

$f=\frac{E}{h}\\\\f=\frac{ 3.7 * 10^{18}}{6.626*10^{-34}}$

$f-=5.58*10^{51}Hz$

Therefore

The frequency of a photon that has an energy of 3.7 × 10-18 j is

$f-=5.58*10^{51}Hz$

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