Respuesta :
We know the initial and final angular speed of the grindston, and also the time t=4.0 s, so by using these data we can find the angular acceleration of the grindstone:
[tex]\alpha= \frac{\omega_f - \omega_i}{t}= \frac{12.0 rad/s-8.0 rad/s}{4.0 s}=1 rad/s^2 [/tex]
And then we can find the total angle covered by the grindstone during the time t=4.0 s:
[tex]\theta= \omega_i t + \frac{1}{2} \alpha t^2 = (8.0 rad/s)(4.0 s)+ \frac{1}{2}(1.0 rad/s^2)(4.0 s)^2=40 rad [/tex]
The average angular speed of the grindstone is the angular speed it would have when covering the angular distance of 40 rad in 4.0 s in uniform angular motion, so
[tex]\omega_{avg} = \frac{\theta}{t}= \frac{40 rad}{4.0 s}=10 rad/s [/tex]
[tex]\alpha= \frac{\omega_f - \omega_i}{t}= \frac{12.0 rad/s-8.0 rad/s}{4.0 s}=1 rad/s^2 [/tex]
And then we can find the total angle covered by the grindstone during the time t=4.0 s:
[tex]\theta= \omega_i t + \frac{1}{2} \alpha t^2 = (8.0 rad/s)(4.0 s)+ \frac{1}{2}(1.0 rad/s^2)(4.0 s)^2=40 rad [/tex]
The average angular speed of the grindstone is the angular speed it would have when covering the angular distance of 40 rad in 4.0 s in uniform angular motion, so
[tex]\omega_{avg} = \frac{\theta}{t}= \frac{40 rad}{4.0 s}=10 rad/s [/tex]
The average angular speed of the grindstone is 10 rad/s
[tex]\texttt{ }[/tex]
Further explanation
Let's recall Angular Speed formula as follows:
[tex]\boxed{ \omega = \omega_o + \alpha t }[/tex]
[tex]\boxed{ \theta = \omega_o t + \frac{1}{2} \alpha t^2 }[/tex]
[tex]\boxed{ \omega^2 = \omega_o^2 + 2 \alpha \theta }[/tex]
[tex]\boxed{ \theta = \frac{( \omega + \omega_o )}{2} t }[/tex]
where :
ω = final angular speed ( rad/s )
ω₀ = initial angular speed ( rad/s )
α = angular acceleration ( rad/s² )
t = elapsed time ( s )
θ = angular displacement ( rad )
[tex]\texttt{ }[/tex]
Given:
radius of the grindstone = R = 4.0 m
initial angular speed = ω₀ = 8.0 rad/s
final angular speed = ω = 12 rad/s
elapsed time = t = 4.0 seconds
Asked:
average angular speed = ?
Solution:
Firstly , we will calculate angular displacement as follows:
[tex]\theta = \frac{( \omega + \omega_o )}{2} t [/tex]
[tex]\theta = \frac{ ( 12 + 8.0 ) }{2} \times 4.0[/tex]
[tex]\theta = 10 \times 4.0[/tex]
[tex]\boxed {\theta = 40 \texttt{ rad}}[/tex]
[tex]\texttt{ }[/tex]
Next , we could calculate the average angular speed as follows:
[tex]\texttt{average angular speed} = \theta \div t[/tex]
[tex]\texttt{average angular speed} = 40 \div 4.0[/tex]
[tex]\boxed{\texttt{average angular speed} = 10 \texttt{ rad/s}}[/tex]
[tex]\texttt{ }[/tex]
Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
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- The Acceleration Due To Gravity : https://brainly.com/question/4189441
- Moment of Inertia : https://brainly.com/question/13796477
- The Ratio of the Moments of Inertia : https://brainly.com/question/2176655
[tex]\texttt{ }[/tex]
Answer details
Grade: High School
Subject: Physics
Chapter: Rotational Dynamics
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