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Mixerz Mixerz
  • 18-04-2018
  • Mathematics
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what is the 4th term in the sequence b(n)=1(-2)^n-1

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Аноним Аноним
  • 18-04-2018
[tex]b(n)=1(-2)^n-1[/tex]

When n = 4, 
[tex]b(4)=1(-2)^4-1[/tex]

[tex]b(4)=16-1[/tex]

[tex]b(4)=15[/tex]

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[tex]b(n)=1(-2)^{n-1}[/tex]

When n = 4
[tex]b(4)=1(-2)^{4-1}[/tex]

[tex]b(4)=1(-2)^3[/tex]

[tex]b(4)=1(-8)[/tex]

[tex]b(4)=-8[/tex]

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