Respuesta :

3x-7y-14 = 0

7y = 3x-14

y = (3/7)x - 2

slope of perpendicular line = -1/(3/7) = -7/3

so function f which is perpendicular and has same y-intercept is

y = (-7/3)x - 2

The general form for a straight line is y = mx + c where m is slope and c is y-intercept.

Two lines are perpendicular when the product of their slopes = -1

Given line 3x - 7y - 14 = 0, its slope = 3/7 and y-intercept = -14/7 = -2

So a line perpendicular to the given and has the same y-intercept is

y = (-7/3) x - 2


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