Respuesta :

the first graph x=1 if it's not correct tell me

Answer:

The 1st graph represents the given equation.

Step-by-step explanation:

We are given the equation [tex]y^2=-4x[/tex]

Now, as we know,

If in the equation of a parabola 'y' is squared, then the parabola opens left or right.

So, the given parabola opens left or right.  ............(1)

If in the equation of a parabola [tex]y^2=4ax[/tex], the value of 'a' is negative, then the parabola opens downwards or left.

Since, in the given parabola, value of 'a' is -1.

So, the parabola opens downwards or right. ...........(2)

Hence, from (1) and (2), we get,

The parabola [tex]y^2=-4x[/tex] opens to the left.

Moreover, the focus of the parabola [tex](y-k)^2=4p(x-h)[/tex] is (h+p,k) and the directrix is x= -p

So, the focus of [tex]y^2=-4x[/tex] is (0-1,0) i.e. (-1,0) and the directrix is x= 1.

So, the 1st graph represents the given equation.

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