Respuesta :
Income of the first account after x years:
[tex]1,850(1.026)^x[/tex]
Income of the second account after x years:
[tex]2,015(1.015)^x[/tex]
Equating the above tw values we get the equation:
[tex]1,850(1.026)^x=2,015(1.015)^x[/tex]
Solving the above equation for x:
[tex]x=8[/tex]
Answer 8 years.
[tex]1,850(1.026)^x[/tex]
Income of the second account after x years:
[tex]2,015(1.015)^x[/tex]
Equating the above tw values we get the equation:
[tex]1,850(1.026)^x=2,015(1.015)^x[/tex]
Solving the above equation for x:
[tex]x=8[/tex]
Answer 8 years.
We can write the equation for the amount of money after x years in Tammy's individual retirement account as
1850(1+0.026)^x
and the equation for the amount of money after x years in Tammy's business interest bearing account as
2015(1+0.015)^x
We equate the above expressions to find the number of years x it will take for the amount of money in both accounts to be equal:
1850(1+0.026)^x = 2015(1+0.015)^x
1850(1.026)^x = 2015(1.015)^x <--this is our first answer
(1.026)^x / (1.015)^x = 2015 / 1850
(1.026 / 1.015)^x = 2015 / 1850
Taking the log of both sides of our equation,
x log (1.026/1.015) = log (2015/1850)
number of years x is
x = log (2015/1850) / log (1.026/1.015)
x = 7.926 ≈ 8 years
1850(1+0.026)^x
and the equation for the amount of money after x years in Tammy's business interest bearing account as
2015(1+0.015)^x
We equate the above expressions to find the number of years x it will take for the amount of money in both accounts to be equal:
1850(1+0.026)^x = 2015(1+0.015)^x
1850(1.026)^x = 2015(1.015)^x <--this is our first answer
(1.026)^x / (1.015)^x = 2015 / 1850
(1.026 / 1.015)^x = 2015 / 1850
Taking the log of both sides of our equation,
x log (1.026/1.015) = log (2015/1850)
number of years x is
x = log (2015/1850) / log (1.026/1.015)
x = 7.926 ≈ 8 years