Question

136 grams of barium sulfate are used to make a 2.5 M solution. How many liters of water are needed?

Answer 1

The  number  liters     that  are  needed  to  make   2.5 m  solution  of  BaSO4   is  calculated  as  follows
 find  moles  of  BaSO4 = moles =  mass/molar mass
  =  64g/  233.4 g/mol=  0.583  moles

volume  of  water  =  moles/ molarity
=  0.583  /2.5  =   0.233  L

Answer 2

Answer: 0.23 L

Explanation: Molarity of solution is defined as the number of moles of solute dissolved per liter of the solution.

Formula used :

$Molarity=\frac{n}{V_s}$

where,

n= moles of solute

$n=Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{136g}{233g/mol}=0.58moles$  

$V_s$ = volume of solution in L

Now put all the given values in the formula of molarity, we get

$2.5M=\frac{0.58moles}{V_s}$

$V_s=0.23L$

Therefore, the volume of solution in Liters is 0.23.