Question

please help me with this question I'm don't apex and i have no clue

Answer 1

The table shows the sum of (x-mean)^2 is 46. put this into the equation (s) for standard deviation. "n" is the number of values in the data set (5 x-values).

$s = \sqrt{ \frac{1}{5 - 1}(46) }$
$s = \sqrt{11.5} \\ \\ s = 3.4$