Respuesta :
Hi there,
Area of a circle with 4m = π(2)² = 4π m²
Area of a circle with 6m = π(3)² = 9π m²
Difference = 9π - 9π = 5π = 16 m² (nearest m²)
Answer: 16 m² (Answer B)
Hope it helps,
TF
Area of a circle with 4m = π(2)² = 4π m²
Area of a circle with 6m = π(3)² = 9π m²
Difference = 9π - 9π = 5π = 16 m² (nearest m²)
Answer: 16 m² (Answer B)
Hope it helps,
TF
Answer:
Option b is correct
16 [tex]m^2[/tex]
Step-by-step explanation:
Area of circle (A) is given by:
[tex]A = \pi r^2[/tex]
where, r is the radius of the circle.
As per the statement:
the areas of a circle with diameter 4 m
Formula for Diameter(d) is:
[tex]d = 2r[/tex]
⇒[tex]4 =2r[/tex]
Divide both sides by 2 we get;
r = 2 m
then;
[tex]A= \pi \cdot (2)^2 = 4 \pi[/tex]
It is also given: a circle with diameter 6 m
Similarly;
[tex]6 = 2r'[/tex]
⇒[tex]r' = 3 m[/tex]
then;
[tex]A' = \pi \cdot 3^2 = 9 \pi[/tex]
We have to find the difference in these areas:
[tex]A'-A = 9 \pi -4 \pi = 5 \pi[/tex]
Use [tex]\pi = 3.14[/tex]
then;
[tex]A'-A = 5 \cdot 3.14 = 15.7 m^2 \approx 16 m^2[/tex]
Therefore, the difference in the areas of a circle with diameter 4 m and a circle with diameter 6 m is, [tex]16 m^2[/tex]