Question

Tori wants to increase the temperature of 500 grams of water from 20 c to 100 c if the specific heat of water is 4.18 j g c how much heat is needed

Answer 1

 The  heat  needed is  calculated  as   follows
Q  =  mc  delta  T
m=  mass  =  500g
c =  specific  heat  capacity  =  4.18  j g c
delta T =  change  in temperature    100-  20  =  80  c
Q   is  therefore =  500g  x  4.18 j g c  x  80 c =  167,200j    or in  Kj=  167200/1000=167.2  kj