Answer: The correct option is
(C). The cardinality of event B’s sample space is 4 greater than event A’s.
Step-by-step explanation: We are given to select the correct statement about the cardinalities of the sample spaces of the following events :
Event A : Flipping a coin.
Event B : Rolling a standard number cube.
We know that
there are two possible outcomes for the event of flipping a coin, i.e., Head (H) and Tail (T).
So, the sample space S for event A is given by
S = {H, T} ⇒ n(S) = 2.
And, there are six possible outcomes for the event of rolling a standard number cube, i.e., 1, 2, 3, 4, 5 and 6.
So, the sample space S' for event B is given by
S' = {1, 2, 3, 4, 5, 6} ⇒ n(S'} = 6.
Therefore, the difference in the cardinalities of the events A and B is
n(S') - n(S) = 6 - 2 = 4.
Thus, the cardinality of event B’s sample space is 4 greater than event A’s.
Option (C) is CORRECT.