Answer:
A) (m^7 n^3 n) / m
Step-by-step explanation:
Given:[tex]\frac{m^7 n^3}{m n^-1}[/tex]
Here we have to use exponent rule.
a^-1 = 1/a
So n^-1 = 1/n
Therefore, [tex]\frac{m^7 n^3}{m . \frac{1}{n} }[/tex]
If we have fraction in the denominator, we can flip and multiply, so we get
= (m^7 n^3 n) / m
Answer is A) (m^7 n^3 n) / m
Hope this will helpful.
Thank you.