Respuesta :
The number could be anything because whatever it is it can be quadrupled
Let the original side of the square be x inches.When sides are increased by 4 inches the sides are x+4 inches.
Area of square with side x inches= [tex]x^{2}.[/tex]
Area of square with sides x+ inches=[tex](x+4)^{2}.[/tex]
According to question:The area of a square can be quadrupled by increasing the side length and width by 4 inches.\
Or [tex]4x^{2}=(x+4)^{2}[/tex]
Expanding we have:
[tex]4x^{2}=x^{2}+8x+16.[/tex]
Or,[tex]3x^{2}-8x-16=0.[/tex]
Factoring,
(3x+4)(x-4)=0
3x+4=0 or x=4
x=[tex]-\frac{4}{3}.[/tex] Or x=4.
Sides can not be negative so x=4.
The sides of the square will be 4 inches.
