Question

a violinist plays a note with a wavelength of 0.77955 m. if the speed of the sound is 343 m/s, what pitch is this note?

Answer 1

Answer: The pitch of the note is: 439.99 Hz


Explanation:

Since,

v = fλ

Therefore,
$f = \frac{v}{\lambda}$

Where v = 343m/s
λ = 0.77955 m

Plug-in the values:

$f = \frac{343}{0.77955}$

f = 439.99 Hz(pitch)