Respuesta :
i. 0xBED is a hexadecimal therefore we need to convert it to decimal first for ease of conversion. The calculation would just need B = 11, E = 14, and D = 13.
[tex]13+(14*16)+(11* 16^{2})=3,053 [/tex]
Then we just continuously divide the number by 3 and take the remainder in each step.
NUMBER REMAINDER
3053 2
1017 0
339 0
113 2
37 1
12 0
4 1
1 1
0
Finally we read the remainders from bottom to top to get the number's base 3 representation.
ANSWER: 11012002 (base 3)
ii. We can easily convert the decimal 3217 to binary by continuously dividing the number by 2 and taking the remainder in each step.
NUMBER REMAINDER
3217 1
1608 0
804 0
402 0
201 1
100 0
50 0
25 1
12 0
6 0
3 1
1 1
0
Then, we just read the remainder from bottom to top to get the decimal's binary representation.
ANSWER: 110010010001 (base 2)
[tex]13+(14*16)+(11* 16^{2})=3,053 [/tex]
Then we just continuously divide the number by 3 and take the remainder in each step.
NUMBER REMAINDER
3053 2
1017 0
339 0
113 2
37 1
12 0
4 1
1 1
0
Finally we read the remainders from bottom to top to get the number's base 3 representation.
ANSWER: 11012002 (base 3)
ii. We can easily convert the decimal 3217 to binary by continuously dividing the number by 2 and taking the remainder in each step.
NUMBER REMAINDER
3217 1
1608 0
804 0
402 0
201 1
100 0
50 0
25 1
12 0
6 0
3 1
1 1
0
Then, we just read the remainder from bottom to top to get the decimal's binary representation.
ANSWER: 110010010001 (base 2)
Answer #1
(11012002)3
step by step Explanation
OxBED
in hexadecimal
we can write these as
A=10
B=11
C=12
D=13
E=14
=(13*[tex]16^{0}[/tex])+(14*[tex]16^{1}[/tex])+(11*[tex]16^{0}[/tex])
=13+224+2816=3050
Now we will divide this number by 3 and take reminder aside
to convert it into base 3
Number Reminder
3053 2
1017 0
339 0
113 2
37 1
12 0
4 1
1 1
hence number will be
(11012002)3
Answer #2
(110010010001)2
Explanation
we can onvert 3217 into base 2 by dividing it by 2
and take reminder of the number aside in every step
Number Reminder
3217 1
1608 0
804 0
402 0
201 1
100 0
50 0
25 1
12 0
6 0
3 1
1 1
The number will be
(110010010001)2