Respuesta :
To find the area you will multiply the length by the width.
Because it is a square, these are the same.
A = lw
(2x - 1)(2x -1)
4x^2 -4x + 1(the last choice)
To get this multiply the first 2 terms in each parenthesis.
2x(2x)= 4x^2
Then multiply the first term in the first ( )by the last term in the last ( ).
2x(-1) = -2x
and then multiply last term in the 1st ( ) by the first term in the last ( ).
Same as above = -2x
Finally, multiply the last terms in both parenthesis
-1(-1)= 1
Because it is a square, these are the same.
A = lw
(2x - 1)(2x -1)
4x^2 -4x + 1(the last choice)
To get this multiply the first 2 terms in each parenthesis.
2x(2x)= 4x^2
Then multiply the first term in the first ( )by the last term in the last ( ).
2x(-1) = -2x
and then multiply last term in the 1st ( ) by the first term in the last ( ).
Same as above = -2x
Finally, multiply the last terms in both parenthesis
-1(-1)= 1
Answer:
D) 4x2 − 4x + 1
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