The power dissipated by the motor is given by:
[tex]P=VI[/tex]
where V is the voltage of the battery and I is the current flowing in the circuit.
In our problem, the voltage is V=12 V and the current is I=246 A, so we can calculate the power dissipated by the motor using the previous equation:
[tex]P=(12 V)(246 A)=2952 W[/tex]