Question

Calculate the molarity of a solution containing 400g cuso4 in 4.00 l of solution

Answer 1

Molarity is defined as the number of moles of solute dissolved in 1 L of solution. 
The mass of CuSO₄ - 400 g
molar mass of CuSO₄ - 159.5 g/mol
Therefore number of CuSO₄ moles - 400 g/ 159.5 g/mol = 2.51 mol
the volume of the solution is - 4.00 L
We need to find the number of moles in 1.00 L 
If 4.00 L contains - 2.51 mol 
Number of moles in 1.00 L - 2.51 mol / 4.00 L = 0.628 mol
Molarity - 0.628 M

Answer 2

The molarity of a solution containing 400g CuSO₄ in 4.00 l of solution is 0.6275 M.

What is molarity?

Molarity is the measure of the concentration of any solute in per unit volume of the solution.

Step1: calculating the moles of $CuSO_4$

mass = 400 g

Molar mass of $CuSO_4$ is 159.5 g/mol

$\rm Number\;of \;moles= \dfrac{mass}{molar\;mass}\\\\\rm Number\;of \;moles= \dfrac{400}{159.5 g/mol } = 2.51 \;mol$

Step 2: calculate the molarity

Mole is 2.51 mol

Volume is 4.00 L

$\rm M = \dfrac{n}{V}\\\\M = \dfrac{2.51}{4.00}= 0.6275\; M$

Thus, the molarity of copper sulfate is 0.6275 M

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