Question

It takes 1200 j of work to lift the car high enough to change a tire.how much work must be done by the person operating the jack if the jack is 25 percent efficient?

Answer 1

 Simply divide 1200 j by 25%

$1200 J / \frac{25}{100} = 1200 J * \frac{100}{25} = 4800 J$

The answer would be 4800 J

Answer 2

The amount of work that must be done by the person to operate the jack is 4800 J

What is efficiency?

This can be defined as the capacity to achieve a given task with little or no waste. Mathematically, it can be expressed as

Efficiency = (output / input) × 100

How to determine the work input

• Output = 1200 J
• Efficiency = 25%
• Input = ?

Efficiency = (output / input) × 100

25% = 1200 / input

0.25 = 1200 / input

Cross multiply

0.25 × input = 1200

Divide both sides by 0.25

Input = 1200 / 0.25

Input = 4800 J

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