Question

whats the area of a polygon with vertices A(2,3) B(12,3) C(6,0) and D(2,0)

Answer 1

this shape is trapezoid

top of the trapezoid is 10 (12-2)

and the bottom is 4 (6-2)

the height in 3 (3-0)


so the area will be
$((10+4) \times 3) \div 2 \\ = (14 \times 3) \div 2 = 42 \div 2 \\ = 21$
the area is 21