Question

Is it possible for two numbers to have a difference of 8, and a sum of 1?

Answer 1

Let x be the first number and y be the second number. If a difference of these numbers is 8, then x-y=8. If a sum of these two numbers is 1, then x+y=1.

Solve the system of equations $\left \{ {{x-y=8} \atop {x+y=1}} \right.$ by adding two equations:

$x-y+x+y=8+1,\\ 2x=9,\\ x=4.5$.

Hence y=1-x=1-4.5=-3.5.

Answer: the difference of 4.5 and -3.5 is 8 and the sum is 1.

Answer 2

It is possible the 2 numbers are - 3.5 and 4.5

let

the numbers be x and y

Two numbers to have a difference of 8 will be

• x - y = 8

sum of 1

• x + y = 1

combine the equation

x - y = 8

x + y = 1

2y = -7

y = -7 / 2

y = - 3.5

x + 3.5  =8

x = 8 - 3.5

x = 4.5

The numbers are 4.5 and -3.5

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