Data Given: Molarity = 0.425 mol/L Volume = 335 mL Moles = ? Solution: First of all convert volume from mL into L.
V = 335 / 1000 = 0.335 L Applying formula of Molarity, Molarity = moles of solute / Volume of solution Solving for moles, Moles = Molarity × Volume Putting values, Moles = 0.425 molL⁻¹ ₓ 0.335 L
Moles = 0.142 moles Results: Hence, when 0.142 moles of Ammonium nitrate taken and is added with enough water to make a volume of 335 mL, the molarity of the resulting solution will be 0.425 mol/dm³.
