Respuesta :
Answer:
Equation of line in point slope form is:
[tex]y=-\dfrac{1}{5}(x+3)+2[/tex]
Step-by-step explanation:
The point-slope form of the equation is:
y= mx + c
The equation of line passing through (a,b) and (c,d) is given by:
[tex]y-b=\dfrac{d-b}{c-a}(x-a)[/tex]
firstly we find equation of line passing through (-3,2) and (2,1) and then convert it to point-slope form.
[tex]y-2=\dfrac{1-2}{2+3}(x+3)[/tex]
[tex]y-2=-\dfrac{1}{5}(x+3)[/tex]
[tex]y=-\dfrac{1}{5}(x+3)+2[/tex]
Hence, Equation of line in point slope form is:
[tex]y=-\dfrac{1}{5}(x+3)+2[/tex]