Respuesta :
2 CH₃CH₂CH₃ + 2 Cl₂ → CH₃CH(Cl)CH₃ + CH₃CH₂CH₂Cl + 2 HCl
so according to balanced equation we notice that:
2 mole of propane reacts with 2 moles of Cl₂, so 6 moles of propane will need to react completely with 6 moles Cl₂ (This mean Cl₂ present in excess and propane is the Limiting reagent)
2 mole C₃H₈ gives 2 moles HCl
6 moles C₃H₈ gives ? moles HCl
by cross multiplication we have 6 moles of HCl formed
so according to balanced equation we notice that:
2 mole of propane reacts with 2 moles of Cl₂, so 6 moles of propane will need to react completely with 6 moles Cl₂ (This mean Cl₂ present in excess and propane is the Limiting reagent)
2 mole C₃H₈ gives 2 moles HCl
6 moles C₃H₈ gives ? moles HCl
by cross multiplication we have 6 moles of HCl formed
Answer:
20
Explanation:
20 mol of cl2 / 4 cl2 = 5 for the equivalence
5* 4 cl = 20
because one in completeely used, cl2 is the limiting reagent,