Respuesta :
I believe it is equivalent.
There is 1 "x" in x+2y+3z and in z+y+z+x+y+z
There are 2 "y's" in z+y+z+x+y+z and in x+2y+3z
There are 3 "z's" in x+2y+3z and in z+y+z+x+y+z
So, yes they should be equal
There is 1 "x" in x+2y+3z and in z+y+z+x+y+z
There are 2 "y's" in z+y+z+x+y+z and in x+2y+3z
There are 3 "z's" in x+2y+3z and in z+y+z+x+y+z
So, yes they should be equal