Respuesta :
Yo faith!
Question 3: Use the equation y= mx + b where m equals slope or the rate of change and b equals the y-intercept.
We already have b, which is 100. The reason why it's 100 is because the y-intercept is where the line crosses directly over the y-intercept. To do so, the x-value must be 0.
Thus y = mx + 100
The slope/ROC can easily be said to be -10 as the x value changes by adding 1 and the y value changes by subtracting 10. However, let's just presume that we didn't know this and couldn't use mental math.
To calculate the slope, we'll use the formula [tex] \frac{y^2 - y^1}{x^2 - x^1}[/tex] Take two points and insert them. I've chosen them for you:
1. (1,90)
2. (2,80)
[tex] \frac{80 - 90}{2-1} [/tex] ⇒[tex] \frac{-10}{1} [/tex] ⇒ -10
Therefore your equation, Faith, is y = -10x + 100
Question 1 of C:
Graph - If the ordered-pair points formulate a straight line.
Table - Constant rate of change/slope for the x and y values.
Equation - No exponents are present.
Question 2 of C: Not sure what ''previous problems'' are given that they are not supplied.
Question 3: Use the equation y= mx + b where m equals slope or the rate of change and b equals the y-intercept.
We already have b, which is 100. The reason why it's 100 is because the y-intercept is where the line crosses directly over the y-intercept. To do so, the x-value must be 0.
Thus y = mx + 100
The slope/ROC can easily be said to be -10 as the x value changes by adding 1 and the y value changes by subtracting 10. However, let's just presume that we didn't know this and couldn't use mental math.
To calculate the slope, we'll use the formula [tex] \frac{y^2 - y^1}{x^2 - x^1}[/tex] Take two points and insert them. I've chosen them for you:
1. (1,90)
2. (2,80)
[tex] \frac{80 - 90}{2-1} [/tex] ⇒[tex] \frac{-10}{1} [/tex] ⇒ -10
Therefore your equation, Faith, is y = -10x + 100
Question 1 of C:
Graph - If the ordered-pair points formulate a straight line.
Table - Constant rate of change/slope for the x and y values.
Equation - No exponents are present.
Question 2 of C: Not sure what ''previous problems'' are given that they are not supplied.