Question

How many moles of sodium hydroxide will be produced from the complete reaction of 15.0 g of sodium?

Answer 1

The reaction of sodium to produce sodium hydroxide is as follows
Na +2 $H_2O$ ---->  NaOH + $H_2$

So the mole ratio between Na and NaOH is 1 to 1 the moles would be equal to each other

To find the moles of Na we take the mass of the Na divide it by the molecular weight of Na (23)
mol Na = $\frac{15}{23} = 0.652$ mol Na = mol NaOH

Answer 2

Answer: The number of moles of NaOH produced are 0.652 moles

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sodium = 15.0 g

Molar mass of sodium = 23 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium}=\frac{15.0g}{23g/mol}=0.652mol$

The chemical equation for the formation of NaOH follows:

$2Na+2H_2O\rightarrow 2NaOH+H_2$

By Stoichiometry of the reaction:

2 moles of sodium produces 2 moles of NaOH

So, 0.652 moles of sodium will produce= $\frac{2}{2}\times 0.652=0.652mol$ of NaOH

Hence, the number of moles of NaOH produced are 0.652 moles